c++11:iota

iota:

Fills the range [first, last) with sequentially(循环的) increasing values, starting with value and repetitively(重复地) evaluating ++value.

Parameters

　　first, last:the range of elemets to fill with sequentially increasing values starting with value

　　vaule: intial value to store, the expression ++value must be well-formed　　

Return value

(none)

Possible implementation

template<class ForwardIterator, class T>

void iota(ForwardIterator first, ForwardIterator last, T value)

{

    while(first != last) {

        *first++ = value;

        ++value;

    }

}

我的例子：

   #include <numeric>

   #include <vector>

   #include <iostream>

   using namespace std;

   int main()

   {

       int a[];

       iota(a, a+, );

      for (auto &r: a)

          cout << r ;

      cout << endl;

      vector<int> va(5);

      iota(va.begin(), va.end(), );

      for (auto &v : va)

          cout << v << " ";

      cout << endl;

      vector<vector<int>::iterator> vb(va.size());

      itoa(vb.begin(), vb.end(), va.begin());

      for (auto &v : vb)

          cout << *v << " ";

      cout << endl;

  }

输出结果：

　　10，11， 12， 13， 14

巴特西

c++11:iota

Parameters

first, last:the range of elemets to fill with sequentially increasing values starting with value

vaule: intial value to store, the expression ++value must be well-formed

Return value

Possible implementation

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