题意：对比新老字典的区别：内容多了、少了还是修改了。

代码：（Accepted，0.000s）

//UVa12504 - Updating a Dictionary

//#define _XieNaoban_

#include<iostream>

#include<sstream>

#include<string>

#include<vector>

#include<map>

using namespace std;

int T;

int main()

{

#ifdef _XieNaoban_

    freopen("in.txt", "r", stdin);

#endif

    ios::sync_with_stdio(false);

    cin >> T;

    cin.ignore();

    while (T--) {

        map<string, string> dic;

        for (int i(0);i < 2;++i) {

            string line, key, value;

            getline(cin, line);

            for (auto &r : line)

                if (r == ',' || r == ':' || r == '{' || r == '}') r = ' ';

            istringstream in(line);

            while (in >> key) {

                in >> value;

                if (i) {

                    auto d(dic.find(key));

                    if (d != dic.end()) {

                        if (d->second != value) d->second = "*";//changed

                        else d->second = '&';//not changed

                    }

                    else dic[key] = "+";//increased

                }

                else dic[key] = value;

            }

        }

        vector<string> inc, rmv, chg;

        for (const auto& r : dic)

            switch (r.second[0])

            {

            case '+': inc.push_back(r.first);break;

            case '*': chg.push_back(r.first);break;

            case '&': break;

            default:  rmv.push_back(r.first);break;

            }

        if (inc.empty() && rmv.empty() && chg.empty())

            cout << "No changes\n";

        else {

            if (!inc.empty()) {

                cout << '+' << inc[0];

                for (auto i(inc.begin() + 1);i != inc.end();++i)

                    cout << ',' << *i;

                cout << '\n';

            }

            if (!rmv.empty()) {

                cout << '-' << rmv[0];

                for (auto i(rmv.begin() + 1);i != rmv.end();++i)

                    cout << ',' << *i;

                cout << '\n';

            }

            if (!chg.empty()) {

                cout << '*' << chg[0];

                for (auto i(chg.begin() + 1);i != chg.end();++i)

                    cout << ',' << *i;

                cout << '\n';

            }

        }

        cout << '\n';

    }

    return 0;

}

分析：这题很水，轻松AC，没啥好说的。