#include <stdio.h>

 /*函数声明*/

 void digui(int n);

 int main()

 {

   int n=;

   digui(n);

   return ;

 }

 void digui(int n)

 {

   printf("level1-value of %d\n",n);

   if(n>){

     digui(n-);

   }

   printf("level2-value of %d\n",n);

 }

[zsd@TOMCAT ~]$ ./test03

level1-value of

level1-value of

level1-value of

level1-value of

level1-value of

level1-value of

level1-value of

level1-value of

level1-value of

---------------------------邪恶的分割线------------------------

level2-value of

level2-value of

level2-value of

level2-value of

level2-value of

level2-value of

level2-value of

level2-value of

level2-value of 

(gdb) run

Starting program: /home/zsd/test03debug

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);                  //开始第一次向下递归，递归数为9

(gdb)

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);                 //向下递归，递归数为8

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:

          digui(n-);                 //一直到这里，递归数为2.这个时候，上面递归的每一个函数digui(2),digui(3)....digui(10)有最后一条printf("level2-value of %d\n",n);语句没有执行。

(gdb) continue

Continuing.

level1-value of 

Breakpoint , digui (n=) at test03.c:18   //digui(2)执行printf("level2-value of %d\n",n);语句

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:18   //digui(3)执行printf("level2-value of %d\n",n);语句

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:18   //以上述递推，一直到digui(10)执行完毕。

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Breakpoint , digui (n=) at test03.c:

        printf("level2-value of %d\n",n);

(gdb) continue

Continuing.

level2-value of 

Program exited normally.