oracle一列中的数据有多个手机号码用逗号隔开，我如何分别取出来？

ID      NUMBER
1       137xxxx,138xxxx
取出来成
ID    NUMBER
1     137xxxx
1     138xxxx

create table test

(id int,

phone varchar2(200));

insert into test values (1,'13811111111,13311111111,13900000000');

insert into test values (2,'15811111111,15911111111,18800000000');

第一种方式

select id,c from

(with t as (select id,phone c from test)

select id,substr(t.ca,instr(t.ca, ',', 1, c.lv) + 1,instr(t.ca, ',', 1, c.lv + 1) - (instr(t.ca, ',', 1, c.lv) + 1)) AS c

from (select id,',' || c || ',' AS ca,length(c || ',') - nvl(length(REPLACE(c, ',')),0) AS cnt FROM t) t,

(select LEVEL lv from dual CONNECT BY LEVEL <= 100) c where c.lv <= t.cnt)

order by id

SELECT id,

regexp_substr(phone, '[^,]+', 1, LEVEL) mobile

FROM test

CONNECT BY PRIOR id = id

AND PRIOR dbms_random.VALUE IS NOT NULL

AND LEVEL <= length(phone) - length(REPLACE(phone, ',')) + 1

巴特西