python学习 2数学公式

2024-04-10 01:40:09

递归

def fact(n):

	if n <= 1:

		return 1

	else:

	  return n * fact(n - 1)

斐波那契数列: 第0项是0，第1项是1,从第2项开始，每一项都等于前两项之和

def fib(n):

  i = 2

  arr = [0, 1]

  while n > 2:

    arr.append(arr[i - 1] + arr[i - 2])

    n -= 1

    i += 1

  return arr

//

MemoTable = {}

def MemoizedFib(n):

    if n <= 2:

        return 1

    if n in MemoTable:

        return MemoTable[n]

    MemoTable[n] = MemoizedFib(n-1) + MemoizedFib(n-2)

    return MemoTable[n]

利用牛顿迭代法求平方根

def sqrt(x):

    def average(a, b):

        return (a + b) / 2.0

    def is_good_enough(guess):

        return (abs((guess * guess) - x) < 0.001)

    def improve(guess):

        return average(guess, x / guess)

    def sqrt_iter(guess):

        if is_good_enough(guess):

            return guess

        else:

            return sqrt_iter(improve(guess))

    return sqrt_iter(1.0)

求最大公约等数

def gcd(x, y):

    result = x

    if y != 0:

        result = gcd(y, x % y)

    return result

汉诺塔

def TowerOfHanoi(n, a, b, tmp):

    if n == 1:

        b.append(a.pop())

    else:

        TowerOfHanoi(n-1, a, tmp, b)

        b.append(a.pop())

        TowerOfHanoi(n-1, tmp, b, a)

stack1 = [4,3,2,1]

stack2 = []

stack3 = []

TowerOfHanoi(len(stack1), stack1, stack3, stack2)

list map

def map(func, lst):

  if lst == []:

    return []

  else:

    return [func(lst[0])] + map(func, lst[1:])

def halveElements(lst):

    return map(lambda x: x / 2.0, lst)

input = [2, 4, 6, 8, 10]

output = halveElements(input)

求平方和

def summation(low, high, f, next):

    s = 0

    x = low

    while x <= high:

        s = s + f(x)

        x = next(x)

    return s

def sumsquares(low, high):

    return summation(low, high, lambda x: x**2, lambda x: x+1)

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